24a^2+36a=21a+28

Solution for 24a^2+36a=21a+28 equation:

24a^2+36a=21a+28

We move all terms to the left:

24a^2+36a-(21a+28)=0

We get rid of parentheses

24a^2+36a-21a-28=0

We add all the numbers together, and all the variables

24a^2+15a-28=0

a = 24; b = 15; c = -28;
Δ = b2-4ac
Δ = 152-4·24·(-28)
Δ = 2913
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{2913}}{2*24}=\frac{-15-\sqrt{2913}}{48}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{2913}}{2*24}=\frac{-15+\sqrt{2913}}{48}
$